Table.Partition

Syntax

  
Table.Partition(table as table, column as text, groups as number, hash as function) as list

About

Partitions the table into a list of groups number of tables, based on the value of the column and a hash function. The hash function is applied to the value of the column row to obtain a hash value for the row. The hash value modulo groups determines in which of the returned tables the row will be placed.

• table: The table to partition.
• column: The column to hash to determine which returned table the row is in.
• groups: The number of tables the input table will be partitioned into.
• hash: The function applied to obtain a hash value.

Example 1

Partition the table ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}) into 2 tables on column [a], using the value of the columns as the hash function.

Usage

Table.Partition(
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 1, b = 4],
        [a = 2, b = 4],
        [a = 1, b = 4]
    }),
    "a",
    2,
    each _
)

Output

{
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 2, b = 4]
    }),
    Table.FromRecords({
        [a = 1, b = 4],
        [a = 1, b = 4]
    })
}